MATH SOLVE

4 months ago

Q:
# please help it’s due tomorrow

Accepted Solution

A:

Step-by-step explanation:1) m<CDN = m<CDE - m<NDE = 180-156 = 24°2) m<KLV = m<KLM - m<VLM = 178-158 = 20°3) m<UVW = m<UVT + m<TVW 172 = 21x+1+149x+1 = 170x+2 Subtract 2, 172-2 = 170x => 170 = 170x. So, x=14) m<ABC = m<ABN + m<NBC 100 = 2x+13+5x+17 100 = 7x+30 70 = 7x. => x=105) m<JKL = m<JKE +m<EKL 129 = x+88+43+x 129 = 2x+131 -2 = 2x => x=-1 m<JKE = x+88 = -1+88 = 87°6) m<GHI = m<GHK + m<KHI 178 = x+40+x+162 178 = 2x+202 -24 = 2x => x=-12 m<GHK = x+40 = -12+40 = 28°7) m<ABC = m<ABL + m<LBC 23x+8 = 29+21x-7 2x = 14 => x=7 m<LBC = 21x-7 = 21*7 - 7 = 147 - 7 = 140°