Q:

Suppose a Railroad rail is 3 kilometers and it expands on a hot day by 20 centimeters in length. Approximately how many meters would the center of the rail rise above the ground

Accepted Solution

A:
Answer:Center of the rail rise above the ground in 17 m.Solution: The railroad rail is 3 km = 3000 meter It expands 20 cm = 0.2 meter on hot day in length So it will form a triangle with base 3000 m and the equal sides will be [tex]\frac{3000+0.2}{2} meter = 1500.1 meter[/tex]Let us assume that the center of the rail will raise x meter. So using Pythagoras theorem, Β [tex]x^{2}+1500^{2}=1500.1^{2}[/tex][tex]x^{2}=1500.1^{2}-1500^{2}[/tex][tex]x^{2}=(1500.1+1500)(1500.1-1500)[/tex][tex]x=3000.1\times0.1[/tex][tex]x^{2}=300.01[/tex]Taking square roots on both sides we get, [tex]x=17(\text {approx})[/tex]So, the rail raise 17 meter from the ground .