Determine the discriminant for the quadratic equation β3 = x2 + 4x + 1. Based on the discriminant value, how many real number solutions does the equation have?Discriminant = b2 β 4ac real number solutions
Accepted Solution
A:
-3 = x^2 + 4x + 1
0 = x^2 + 4x + 1 + 3
0 = x^2 + 4x + 4
Discriminant is b^2 - 4ac.
4^2 - 4(1)(4)
16 - 4(4)
16 - 16 = 0
Discriminant Rules:
1. If bΒ²-4ac is negative, there are no real answers. 2. If bΒ²-4ac is zero, there is one real answer. 3. If bΒ²-4ac is positive, there are two real answers.